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X5y5. Get your answers by asking now. Most people learn the factorization of but if you forget you can divide that problem out using long division. Everything in the middle cancels out and we end up with x 5 y 5.
For fun lets try x 11 y 11. Ask question 100. For n odd integer the following identity holds xn yn x yxn 1 xn 2y cdots xyn 2 yn 1 or xn ynxyxn 1 xn 2y cdots xyn 2 yn 1 hence for our case we have that x5y5xyx4 x3 yx2 y2 x y3y4.
X y x4 x3y x2y2 xy3 y4 x5 y5 all the cross terms cancel when you multiply it out the fourth degree term can be factored into two quadratics but the coefficients will be. X5 y5 first note that if xy then x5 y5 0. X 4 x 3 y x 2 y 2 xy 3 y 4 x y x 5 0x 4 y 0x 3 y 2 0x 2 y 3 0xy 4 y 5 x 5 x 4 y x 4 y 0x 3 y 2 x 4 y x 3 y 2 x 3 y 2 0x 2 y 3 x 3 y 2 x 2 y 3 x 2 y 3.
Then wed have x yx 10 x 9 y x 8 y 2 x 7 y 3 x 6 y 4 x 5 y 5 x 4 y 6 x 3 y 7 x 2 y 8 xy 9 y 10. Join yahoo answers and get 100 points today. Hence we can deduce that x y is a factor.
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